diff --git a/skibur-just-in-time/skibur-just-in-time.py b/skibur-just-in-time/skibur-just-in-time.py
new file mode 100755
index 0000000..4dca7c4
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+++ b/skibur-just-in-time/skibur-just-in-time.py
@@ -0,0 +1,59 @@
+#!/usr/bin/env python3
+
+# Link: https://crackmes.one/crackme/63c4ee1a33c5d43ab4ecf49a
+
+# Conditions that must be fulfilled for the key to be valid:
+# key[0] == '%'
+# key[1] << t == 200
+# key[2] << t == 212
+# key[3] == 'k'
+# key[4] << t == 80
+# key[5] & 1073741823 == 57
+# key[6] == '^'
+# key[7] << t == 246
+# key[8] & 1073741823 == 46
+# key[9] == 'f'
+# key[10] << t == 128
+# key[11] & 1073741823 == 49
+# key[12] == 'F'
+# key[13] << t == 104
+# (t = (localtime() % 10) % 3) => t either 0, 1, or 2
+
+# After these conditions are met the printable string (either "Incorrect password." or
+# "Correct password. Congratulation!") is decoded by shifting each of the string's
+# character's value to the right by one and subtracting 5 from that.
+
+
+from string import ascii_letters, digits, punctuation
+import itertools
+
+key = ["%", "", "", "k", "", "", "^", "", "", "f", "", "", "F", ""]
+
+for c in itertools.chain(*[ascii_letters, digits, punctuation]):
+    shift = ord(c) << 1
+
+    match shift:
+        case 200:
+            key[1] = c
+        case 212:
+            key[2] = c
+        case 80:
+            key[4] = c
+        case 246:
+            key[7] = c
+        case 128:
+            key[10] = c
+        case 104:
+            key[13] = c
+
+    band = ord(c) & 0x3FFFFFFF
+
+    match band:
+        case 57:
+            key[5] = c
+        case 46:
+            key[8] = c
+        case 49:
+            key[11] = c
+
+print(f"{''.join(key)}")